{"id":848,"date":"2021-12-01T20:29:41","date_gmt":"2021-12-01T19:29:41","guid":{"rendered":"https:\/\/anclademia.com\/?p=848"},"modified":"2021-12-01T20:29:54","modified_gmt":"2021-12-01T19:29:54","slug":"correccio-total","status":"publish","type":"post","link":"https:\/\/anclademia.com\/ca\/blog\/correccion-total\/","title":{"rendered":"Correcci\u00f3 total"},"content":{"rendered":"<p><strong>10.7.- CORRECCI\u00d3 TOTAL <\/strong><\/p>\n\n\n\n<p><strong>10.7.1.- Definici\u00f3<\/strong><\/p>\n\n\n\n<p>\u00c9s el&nbsp;<strong><em>angle que forma el nord d&#039;agulla amb el nord veritable<\/em><\/strong>. \u00c9s a dir, \u00e9s igual a la suma algebraica de la dm i el desviament.<\/p>\n\n\n\n<p><strong>Ct = dm +&nbsp;<\/strong><strong>\u0394<\/strong><\/p>\n\n\n\n<p><strong>10.7.2.- C\u00e0lcul a partir de la declinaci\u00f3 i el desviament<\/strong><\/p>\n\n\n\n<p>Coneguda la declinaci\u00f3 magn\u00e8tica (dm), a trav\u00e9s de la carta, o per ser proporcionada pel problema i conegut el desviament, b\u00e9 per la dada proporcionada pel problema, o b\u00e9 per disposar de la tauleta de desviament, nom\u00e9s cal sumar algebraicament ambdues dades per con\u00e8ixer el c\u00e0lcul, aix\u00ed per exemple si la declinaci\u00f3 magn\u00e8tica \u00e9s 6o NW i el desviament navegant a un rumb determinat \u00e9s de 3o NE, el valor de la correcci\u00f3 total ser\u00e0:<\/p>\n\n\n\n<p><strong><em>Ct = dm + \u0394 = \u2013 6 + (+ 3) = \u2013 3o<br><\/em><\/strong>Important \u00e9s tenir en compte que la\u00a0<strong><em>correcci\u00f3 total varia a cada rumb\u00a0<\/em><\/strong>ja que encara que la dm roman constant el desviament dependr\u00e0 del rumb.<\/p>","protected":false},"excerpt":{"rendered":"<p>10.7.- CORRECCI\u00d3 TOTAL 10.7.1.- Definici\u00f3 \u00c9s l&#039;angle que forma el nord d&#039;agulla amb el veritable nord. \u00c9s a dir, \u00e9s igual a la suma algebraica de la dm i el desviament. Ct = dm + \u0394 10.7.2.- C\u00e0lcul a partir de la declinaci\u00f3 i el desviament Coneguda la declinaci\u00f3 magn\u00e8tica (dm), a trav\u00e9s de la carta, \u2026 <a title=\"Correcci\u00f3 total\" class=\"read-more\" href=\"https:\/\/anclademia.com\/ca\/blog\/correccion-total\/\" aria-label=\"M\u00e9s informaci\u00f3 sobre Correcci\u00f3 total\">Llegiu m\u00e9s<\/a><\/p>","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[1],"tags":[],"class_list":["post-848","post","type-post","status-publish","format-standard","hentry","category-sin-categorizar"],"jetpack_featured_media_url":"","jetpack_sharing_enabled":true,"_links":{"self":[{"href":"https:\/\/anclademia.com\/ca\/wp-json\/wp\/v2\/posts\/848","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/anclademia.com\/ca\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/anclademia.com\/ca\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/anclademia.com\/ca\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/anclademia.com\/ca\/wp-json\/wp\/v2\/comments?post=848"}],"version-history":[{"count":0,"href":"https:\/\/anclademia.com\/ca\/wp-json\/wp\/v2\/posts\/848\/revisions"}],"wp:attachment":[{"href":"https:\/\/anclademia.com\/ca\/wp-json\/wp\/v2\/media?parent=848"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/anclademia.com\/ca\/wp-json\/wp\/v2\/categories?post=848"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/anclademia.com\/ca\/wp-json\/wp\/v2\/tags?post=848"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}